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5-8x=3x^2-12x+2
We move all terms to the left:
5-8x-(3x^2-12x+2)=0
We get rid of parentheses
-3x^2-8x+12x-2+5=0
We add all the numbers together, and all the variables
-3x^2+4x+3=0
a = -3; b = 4; c = +3;
Δ = b2-4ac
Δ = 42-4·(-3)·3
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{13}}{2*-3}=\frac{-4-2\sqrt{13}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{13}}{2*-3}=\frac{-4+2\sqrt{13}}{-6} $
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